Probability Solved Problems

Probability Solved Problems-13
semi-finals and final, home games for a popular team, games for smaller stadia.

semi-finals and final, home games for a popular team, games for smaller stadia.100% is more than 4 standard deviations above the mean Solves problem and discusses assumption of normality.

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We will discuss different probability word problems here.

The problems in probability that have to be deduced in mathematical form from the given statements in English are the probability word problems to be solved. We have 40 white candies, 24 green ones, 12 red ones, 24 yellow ones and 20 blue ones.

Suppose a simple random sample of 100 voters are surveyed from each state.

What is the probability that the survey will show a greater percentage of Republican voters in the second state than in the first state?

 developing a chain of logical reasoning and also, where appropriate, using contextual knowledge to reflect on the answer.

Evidence Statement One Expected Coverage Normal distribution, µ = 782, σ = 158 (a) (i) P(X 600) = 0.1189 (b) Probabilities for the different levy groups calculated.For one tourist: E(levy) = 0.2655 × 5 0.6157 × 8 0.1189 × 12 = 7.6799 E(levy2)= 0.2655 × 52 0.6157 × 82 0.1189 × 122 = 63.1639 SD(levy) = √(63.1639 – 7.67992) = 4.1830 At least two correct calculations of expected value and variance/standard deviation for individual levy or the total levies calculated The variation of the levies is taken into account when determining whether the council should build the reef, by considering the size of the standard deviation of the total levies.Merit Excellence For all 12000 tourists: E(total levies) = 12000 × 7.6799 = 158.80 SD (total levies) = √(12000) × 4.1830 = 8.22 As the expected total is 158.80 with a low standard deviation of 8.22 it is unlikely that the required 0 000 can be reached; so the plan should not go ahead.In one state, 52% of the voters are Republicans, and 48% are Democrats.In a second state, 47% of the voters are Republicans, and 53% are Democrats.If we have selected one candy from the box without peeking into it, find the probability of getting a green or red candy.A Bayes factor is the ratio of the likelihood of one particular hypothesis to the likelihood of another. Assuming normality, P(one game has under 90% occupancy) = 0.079 Assuming attendance of each game is independent, probability is 0.0794 (c) = 3.9 x 10-5 (2 sf).Game attendance is unlikely to be independent with equal probability as games will be held at different venues with different players.If you're behind a web filter, please make sure that the domains *.and *.are unblocked.Probability is a fundamental concept in math and statistics.


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